Question

in a series Sn=5n²-2n then t4=​

Answer 1

☘️ Solution:-

S1 = t1 = 3

.

S2 = 16

t2 = 16 – 3

= 13

.

d = t2 – t1

= 13 – 3

= 10

.

t4 = t1 + 3d

= 3 + 3 + 30

= 33

________________________

☘️ Answer:- t4 = 33

_________________________

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Answer 2

Answer:

S  

n

​  

=5n  

2

+2n(Given)

First term (S  

1

​  

)=5⋅(1)  

2

+2⋅1=7

Sum of first two terms (S  

2

​  

)=5⋅(2)  

2

+2⋅2=24

Therefore,

Second term =S  

2

​  

−S  

1

​  

=24−7=17