Question

In a set of 24 cards, each card is numbered with a different positive integer from 1 to 24. One card will be drawn at random from the set. What is the probability that the card drawn will have either a number that is divisible by both 2 and 3 or a number that is divisible by 7 ?

Answer 1

Answer:

7/24

Step-by-step explanation:

S={1,2,3,4,...22,23,24}

Number divisible by both 2 and 3 are multiples of 6

So E={6,7,12,14,18,21,24}

n(S)=24

n(E)=7

Hence P(E)=7/24