in a set of four integers the average of the two smallest integers is 102,the average of the three smallest integers is 103,the average of all four is 104.which is the greatest of these integers?
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Answers
Answered by
208
let the numbers be w,x,y,z such that z is greatest and w is smallest
so given
w+x/2=102
w+x=204
and also w+x+y/3=103
w+x+y=309
and also w+x+y+z/4=104
w+x+y+z=416
309+z=416
z=416-309
=107
so given
w+x/2=102
w+x=204
and also w+x+y/3=103
w+x+y=309
and also w+x+y+z/4=104
w+x+y+z=416
309+z=416
z=416-309
=107
Answered by
136
Find the sum of all the 4 integers:
Average = 104
Sum = 104 x 4 = 416
Find the sum of the 3 smallest integers:
Average = 103
Sum = 103 x 3 = 309
Find the greatest number:
The greatest number = 416 - 309 = 107
Answer: The greatest number is 107
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