Question

in a set of four numbers,the first three are in G.P.and the last three are in A.P.with a common difference of 6.if the first number is same as the fourth,find the four numbers

Answer 1

hi friend,

<>let the last three numbers of the set which are in A.P be b,b+6,b+12 and the first number be a.

→thus ,the four numbers are a,b,b+6,b+12

given,a=b+12-----(1)

also, given a,b,b+6 are in G.P

by equation (1)

→b+12,b,b+6 are in G.P

→b/(b+12)=(b+6)/b

→b²=(b+6)(b+12)

→b²=b²+18b+72

→18b=-72

→b=-4

→a=-4+12=8

hence the four numbers are 8,-4,2,8


I hope this will help u ;)

Answer 2

hey mate here is the solution hope it helps you