In a set of reactions, ethylbenzene yielded a
product D.
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In presence of alkaline KMnO4, ethylbenzene will undergo oxidation and form benzoic acid. Benzoic acid on reacting with Br2/FeCl3 undergoes halogenation reaction. The addition of Br atom will take place at meta position due to the presence of ring deactivating substituent −COOH group
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