Question

In a set of three lines, a pair of parallel lines is intersected by a transversal. The intersection forms eight special angles. Two of the special angles, ∠A and ∠B, are corresponding angles.
For the set of parallel lines intersected by a transversal, A = 4x and B = 2(x+14).

Use an equation to represent the corresponding angle relationship between A and B.
Use the equation to find the measures of A and B.

Answer 1

Given :-

• A pair of parallel lines is intersected by a transversal.
• ∠A and ∠B, are corresponding angles.
• ∠A = 4x.
• ∠B = 2(x + 14).

Solution :-

Corresponding angles :-

• When two lines are crossed by another line transversal line , the angles in matching corners are called corresponding angles.

• when the two lines are parallel Corresponding Angles are equal.

So,

→ ∠A = ∠B

Putting values we get,

→ 4x = 2(x + 14). ( Equation )

Now, solving this ,

→ 4x = 2(x + 14)

→ 4x = 2x + 28

→ 4x - 2x = 28

→ 2x = 28

Dividing both sides by 2 ,

→ x = 14.

Therefore,

→ ∠A = 4x = 14 * 4 = 56°.

→ ∠B = 2(x + 14) = 2(14 + 14) = 2 * 28 = 56° .

Answer 2

Answer:

A pair of parallel lines is intersected by a transversal.∠A and ∠B, are corresponding angles.∠A = 4x.∠B = 2(x + 14). just had this one trust me on this because I got 100% on my test. All the best Lilly

Step-by-step explanation: