Business Studies, asked by husnaejaz12341, 1 day ago

In a shipment of 20 computers, 3 are defective. Three computers are randomly selected and tested What is the probability that all three are defective iſ the first and second ones are not replaced after being tested?

Answers

Answered by gareemay

0

Answer:

Please mark me the brainliest.

Explanation:

First one 3/20

Second one 2/19

third one 1/18

3/20*2/19*1/18 = 1/(3*20*19) =1/1140

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