In a shipment of 25 hard disks, 6 are defective. If 5 of the disks are selected at random what is the probability that (a) Exactly 1 is defective (b) At least 1 is defective (c) No less than 2 are defective ( at least two are defective)
Can you work the full problem please.
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Answer:
(a) 5c1 ÷ 25c5 = 5 ÷ 53130 = 1/10626
Step-by-step explanation:
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