Math, asked by LouisAaron8725, 1 year ago

In a shooting competition, the probability that rahul will hit the target is 5/7 and the probability that sheela will hit the target is 3/4. So what is the probability that both of them will hit the target

Answers

Answered by nehalk123
3

Answer: 15/28

Step-by-step explanation:

To get the probability, we need to multiply 5/7 by 3/4. This will give us a result of 15/28. Hope this helps.

Answered by aishwaryahk
3

Answer:

The probability that both Rahul and Sheela will hit the target is \frac{15}{28}

Step-by-step explanation:

Let the probability that Rahul will hit the target be P(R) = \frac{5}{7}

Let the probability that Sheela will hit the target be P(S) = \frac{3}{4}

The probability that both will hit the target is given by

= P(R) × P(S)

=(\frac{5}{7} )(\frac{3}{4} )

= \frac{15}{28}

Therefore the probability that both Rahul and Sheela will hit the target is \frac{15}{28}

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