Question

In a shooting test, the probability of hitting the target is 0.2 for A, 0.4 for B, and 0.6 for C. If all of them fire at the target, what is the probability that: I) only two hits ii) at most two hit iii) at best one hits iv) at least one hits v) only one hits?

Answer 1

Answer:

3\4 or 75%

Step-by-step explanation:

The probability for none of them hitting is easiest as there’s only one scenario - everyone misses - so 1/2 * 1/3 * 1/4 = 1/24.

For at most two of them hitting the target, we know that’s equal to 1 - P(everyone hits the target) [as if at least one misses, at most two hit]

= 1 - 1/2 * 2/3 * 3/4 = 1 - 1/1 * 1/3 * 3/4 = 1 - 1/1 * 1/4 = 3/4.