Question

In a show the prices of tickets were rs.15 and 25. Find number of each ticket if 300 were admitted collecting rs.5500

Answer 1

Answer:

Let the cost of an adult ticket = x

Let the cost of an adult ticket = xThe cost of an child ticket = y

Let the cost of an adult ticket = xThe cost of an child ticket = yThen form an first equation as,

Let the cost of an adult ticket = xThe cost of an child ticket = yThen form an first equation as,x+y=100 ----- (1)

Let the cost of an adult ticket = xThe cost of an child ticket = yThen form an first equation as,x+y=100 ----- (1)10x+20y=200 ---- (2)

Let the cost of an adult ticket = xThe cost of an child ticket = yThen form an first equation as,x+y=100 ----- (1)10x+20y=200 ---- (2)By solving the equation (1) 

Let the cost of an adult ticket = xThe cost of an child ticket = yThen form an first equation as,x+y=100 ----- (1)10x+20y=200 ---- (2)By solving the equation (1) y=100−x

Let the cost of an adult ticket = xThe cost of an child ticket = yThen form an first equation as,x+y=100 ----- (1)10x+20y=200 ---- (2)By solving the equation (1) y=100−xPut the value of y in equation (2) 

Let the cost of an adult ticket = xThe cost of an child ticket = yThen form an first equation as,x+y=100 ----- (1)10x+20y=200 ---- (2)By solving the equation (1) y=100−xPut the value of y in equation (2) 10x+20(100−x)=200

Let the cost of an adult ticket = xThe cost of an child ticket = yThen form an first equation as,x+y=100 ----- (1)10x+20y=200 ---- (2)By solving the equation (1) y=100−xPut the value of y in equation (2) 10x+20(100−x)=20010x+2000−20x=200

Let the cost of an adult ticket = xThe cost of an child ticket = yThen form an first equation as,x+y=100 ----- (1)10x+20y=200 ---- (2)By solving the equation (1) y=100−xPut the value of y in equation (2) 10x+20(100−x)=20010x+2000−20x=200−10x=200−2000

Let the cost of an adult ticket = xThe cost of an child ticket = yThen form an first equation as,x+y=100 ----- (1)10x+20y=200 ---- (2)By solving the equation (1) y=100−xPut the value of y in equation (2) 10x+20(100−x)=20010x+2000−20x=200−10x=200−2000−10x=−1800

Let the cost of an adult ticket = xThe cost of an child ticket = yThen form an first equation as,x+y=100 ----- (1)10x+20y=200 ---- (2)By solving the equation (1) y=100−xPut the value of y in equation (2) 10x+20(100−x)=20010x+2000−20x=200−10x=200−2000−10x=−1800x=180 

Let the cost of an adult ticket = xThe cost of an child ticket = yThen form an first equation as,x+y=100 ----- (1)10x+20y=200 ---- (2)By solving the equation (1) y=100−xPut the value of y in equation (2) 10x+20(100−x)=20010x+2000−20x=200−10x=200−2000−10x=−1800x=180 Therefore the cost of a child ticket = Rs. 180

Step-by-step explanation:

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