Question

in a shunted ammeter, only 10% of current passed through the galvanometer of resistance G . the resistance of the shunt is

Answer 1

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by using formula

Rs = Ig Rg / I-Ig

taken I = 100

then Ig = 10% of 100 I.e 10

now , Putting tge values

Rs = 10 * G / 100 - 10

Rs = G / 9

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