In a simple Atwood machine, two unequal masses m1 and m2 are connected by a string going over a clamped light smooth pulley. In a typical arrangement (figure 5−E7), m1 = 300 g and m2 = 600 g. The system is released from rest. (a) Find the distance travelled by the first block in the first two seconds; (b) find the tension in the string; (c) find the force exerted by the clamp on the pulley.
Figure
Answers
Answered by
2
Explanation:
m1= 300g , m2= 600g , u = 0 , let g = 10
As m2 as more mass it is accelerating downwards. So equation of motion of m2
m2g ‐ T = m2a........... (i)
m1 is accelerating upward so eq. of motion is
T - m1g= m1a.............. (ii)
combining eq i and ii
a = (m2 -m1/ m2+m1)× g
a= (600 -300/600+300) × 10
a = 10/3 m/s^2
(a) distance travelled (s) = ut+ 1/2at^2
t=2 sec
s=(0)(2) + 1/2 × 10/3 × 2× 2
s= 20/3 metre
(b) tension (T) = (2×m1×m2/m1+m2)×g
T = (2× 600×300/600+300)×10
T = 4000 N
(c) force (F) = 2T (or) (4×m1×m2/m1+m2)×g
F= 2 × 4000
F= 8000 N
THEREFORE
(a) distance travelled by block in first 2 seconds = 20/3 metre
(b) tension in string = 4000 N
(c) force exerted by string = 8000 N
Similar questions