In a simple axle and wheel, the diameter of the wheel is 180 mm and that of axle 30 mm. If the efficiency of the machine is 80%, find the effort required to lift a load of 100 N.
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Answer:
25 cm
d2 = 10 cm
Load W = 750 N
Efficiency η = 42 % = 0.42
Effort P=70 N
Velocity ratio VR
=
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=
Distancemovedbyload
Distancemovedbyeffort
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=
2
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1
−
�
2
=
2
�
25
−
10
=
2
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15
=
0.1333
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VR=
d
1
−d
2
2D
=
25−10
2D
=
15
2D
=0.1333D
Mechanical advantage
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=
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MA=
Effort
Load
�
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=
�
�
=
750
70
=
10.714
MA=
P
W
=
70
750
=10.714
Efficiency
�
=
�
�
�
�
η=
VR
MA
0.42
=
10.714
0.1333
�
0.42
×
0.1333
�
=
10.714
�
=
10.714
0.055986
=
191.37
�
�
0.42=
0.1333D
10.714
0.42×0.1333D=10.714
D=
0.055986
10.714
=191.37cm
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