In a simple harmonic motion
(a) the maximum potential energy equals the maximum kinetic energy
(b) the minimum potential energy equals the minimum kinetic energy
(c) the minimum potential energy equals the maximum kinetic energy
(d) the maximum potential energy equals the minimum kinetic energy.
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In Simple Harmonic Motion, Relation of Kinetic and Potential energy is given by the formula,
Kinetic Energy = 1/2 k(A² - x²)
Potential energy = 1/2 kx²
For maxima, and minima in Kinetic and Potential energy.
________________________
Kinetic Energy.
Maximum when x = 0.
K.E. = 1/2k(A² -0²) = 1/2kA²
Minimum when x = A.
K.E. = 1/2k(A² - A²) = 0
_________________________
Potential Energy,
Maximum when x = ± A
P.E. = 1/2kA²
Minimum when x = 0
P.E. = 0
From this we can see that minimum potential energy equal the minimum kinetic energy and Maximum Potential energy equal the maximum kinetic energy.
Thus, Option (a). and (b) are correct.
Hope it helps.
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