In a simple harmonic motion
(a) the maximum potential energy equals the maximum kinetic energy
(b) the minimum potential energy equals the minimum kinetic energy
(c) the minimum potential energy equals the maximum kinetic energy
(d) the maximum potential energy equals the minimum kinetic energy.
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Kinetic Energy = 1/2 k(A² - x²)
Potential energy = 1/2 kx²
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Kinetic Energy.
Maximum when x = 0.
K.E. = 1/2k(A² -0²) = 1/2kA²
Minimum when x = A.
_________________________
Potential Energy,
Maximum when x = ± A
P.E. = 1/2kA²
Minimum when x = 0
P.E. = 0
Thus, Option (a). and (b) are correct.
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