Question

In a simple harmonic oscillator, at the mean position
(a) Kinetic energy is minimum, potential energy is maximum
(b) Both kinetic and potential energies are maximum
(c) Kinetic energy is maximum, potential energy is minimum
(d) Both kinetic and potential energies are minimum

Answer 1

Answer:

C. At mean position kinetic energy is maximum and potential energy is minimum.

Explanation:

hope the answer will help you

Answer 2

For a simple harmonic oscillator,

Kinetic Energy at position 'y' can be given as:

$K = \dfrac{1}{2}m\omega^2(A^2 - y^2)$

At mean position y = 0,

K.E(max) = $\dfrac{1}{2}m\omega^2A^2$

Potential Energy at position ' y' can be given as:

$P.E = \dfrac{1}{2}m\omega^2y^2$

At mean positon y = 0,

P.E (minimum)= 0

So, Kinetic energy is maximum, potential energy is minimum.

Hence, Option C is correct.