Question

in a simple harmonic oscillator has got a displacement of 0.02 m and acceleration equal to 2.0 m/s² at any time the angular frequency of the oscillator is equal to​

Answer 1

Explanation:

a=w^2.x

2=w^2.1/50

w^2=100

w=√100

w=10

Answer 2

The angular frequency of the oscillator is equal to 10 rad/s.

Explanation:

It is given that,

Displacement in simple harmonic motion, A = 0.02 m

Acceleration in SMH, $a=2\ m/s^2$

To find,

Angular frequency of the oscillator.

Solution,

The acceleration of the particle in SHM is given by :

$a=A\omega^2$

$\omega=\sqrt{\dfrac{a}{A}}$

$\omega=\sqrt{\dfrac{2}{0.02}}$

$\omega=10\ rad/s$

So, the angular frequency of the oscillator is equal to 10 rad/s. Hence, this is the required solution.

Learn more,

Simple harmonic motion

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