Question

in a simple lifting machine a load of 1400 N is lifted by 50N effort while the load moves up by 0.2 m the effort moves by 6 m .calculate 1) M. A. (2) V. R. (3) efficiency​

Answer 1

Answer:

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Explanation:

1. MA=28
2. VR=30,
3. Eff=93.33%

Answer 2

A simple lifting machine of M.A is 28, V.R is 30 and Efficiency is 93.33%.

Defination of efficiency of machine.

A machine's efficiency measures how well its input energy is turned into useful output energy or work. It is the fraction or percentage of the output divided by the input, and it is a crucial aspect in a machine's usefulness.

Accordind to the question:

(1) The load is 14,00N and effort is 50N.

    $M.A = \frac{load}{effort}$

    $M.A = \frac{1400}{50} \\\\M.A= 28$

(2) Distance moved by effort is 6m,that of load is 0.2m.

$V.R = \frac{6}{0.2} \\\\V.R = 30$

(3) Efficiency.

$= \frac{M.A}{V.R}.100 \\\\\\=\frac{28}{30}.100\\\\= 93.33$

Hence, M.A. is 28, V.R. is 30, and Efficiency is 93.33 percent for a simple lifting machine.

Learn more about efficiency of machine here,

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