In a simple pendulum experiment percentage error in measuring the length is 0.1% and the percentage error in determining time period is 2%. Find the percentage error in determining (l/t^2)
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Answers
Correct option is
Correct option isD
Correct option isD8%
Correct option isD8%Time period, T=2π
Correct option isD8%Time period, T=2π g
Correct option isD8%Time period, T=2π gl
Correct option isD8%Time period, T=2π gl
Correct option isD8%Time period, T=2π gl
Correct option isD8%Time period, T=2π gl
Correct option isD8%Time period, T=2π gl
Correct option isD8%Time period, T=2π gl or g=
Correct option isD8%Time period, T=2π gl or g= T
Correct option isD8%Time period, T=2π gl or g= T 2
Correct option isD8%Time period, T=2π gl or g= T 2
Correct option isD8%Time period, T=2π gl or g= T 2 4π
Correct option isD8%Time period, T=2π gl or g= T 2 4π 2
Correct option isD8%Time period, T=2π gl or g= T 2 4π 2 l
Correct option isD8%Time period, T=2π gl or g= T 2 4π 2 l
Correct option isD8%Time period, T=2π gl or g= T 2 4π 2 l
Correct option isD8%Time period, T=2π gl or g= T 2 4π 2 l The maximum percentage error
Correct option isD8%Time period, T=2π gl or g= T 2 4π 2 l The maximum percentage error g
Correct option isD8%Time period, T=2π gl or g= T 2 4π 2 l The maximum percentage error gΔg
Correct option isD8%Time period, T=2π gl or g= T 2 4π 2 l The maximum percentage error gΔg
Correct option isD8%Time period, T=2π gl or g= T 2 4π 2 l The maximum percentage error gΔg =
Correct option isD8%Time period, T=2π gl or g= T 2 4π 2 l The maximum percentage error gΔg = l
Correct option isD8%Time period, T=2π gl or g= T 2 4π 2 l The maximum percentage error gΔg = lΔl
Correct option isD8%Time period, T=2π gl or g= T 2 4π 2 l The maximum percentage error gΔg = lΔl
Correct option isD8%Time period, T=2π gl or g= T 2 4π 2 l The maximum percentage error gΔg = lΔl +2