Question

in a simple pendulum experiment the length of the pendulum is 90.6 ×10power-2metre. The time period is 1.91 second. write the value of acceleration due to gravity to correct significant figures and round it off.​

Answer 1

Answer:

Given that L = 90.6 x 10^-2 m and T = 1.91 s g = ?

.:g  = 4 pie^2. L

             T

g = 4 pie^2 . ( 90.6 x 10^-2 )

                (1.91)

.: g = 18.73 m/s^2

Explanation:

Since T = 2 pie. square root of L/g

Hope you Understood the Formula used!