Question

In a simultaneous throw of a pair of dice find the probablity of getting a sum greater than 7

Answer 1

Answer:

total number of outcomes=6×6=36(Sum of 2 dice)

P(getting a sum greater than 7)=

1. 2. 3. 4. 5. 6

1 (1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

2 (2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

3 (3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

4 (4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

5 (5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

6 (6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

Now, find the two numbers by adding them you will get greater than 7 number.....

p(getting greater than 7 number)=(2,6),(3,5),(6,3),(4,4),(4,5),(4,6),(5,3),(5,4),(5,5),(5,6),(6,2),(6,3),(6,4),(6,5),(6,6)=15/36

15/36=5/12