Question

in a simultaneous throw of a pair of dice, find the probability of getting: neither 9 or 11 as the sum of the numbers on the faces​

Answer 1

Answer:

5/6

Step-by-step explanation:

There are, in total, 36 equally likely outcomes, corresponding to the 36 pairs (x, y) where x is the number on one particular die, and y is the number on the other.

Of these, there are 4 with sum 9:  (3, 6), (4, 5), (5, 4), (6, 3)

and 2 with sum 11:  (5, 6), (6, 5).

Excluding these 6, there are then 30 outcomes that result in neither 9 nor 11 as the sum.

So the probability of getting neither 9 nor 11 is 30/36 = 5/6.

Hope this helps.