in a simultaneous throw of a pair of dice find the probability of getting an even number on the first die
rdmahendra2:
Probability = Possible no. of outcome/ Total no of events , so there are 6 possible these are (1,2,3,4,5,6) the no of even are (2,4,6) then the probability of it would be 3/6
But there are 2 dice
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10
there are 3 even numbers between 1 to 6 ..so the probability will be 3/6=1/2.
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6
if 2 die it means 1/12
and if only on 1 die then it means
1/6
and if only on 1 die then it means
1/6
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