In a simultaneous throw of two coins the probability of getting at least one head is
1/2 1/3 2/3 3/4
Answers
Answered by
24
Total outcomes = HH , HT , TH , TT
P(At least 1 head) = 3/4
I hope it helps.
Mark it as BRAINLIEST if you find it useful.
P(At least 1 head) = 3/4
I hope it helps.
Mark it as BRAINLIEST if you find it useful.
Answered by
4
Answer:
3/4
Step-by-step explanation:
To Find: In a simultaneous throw of two coins the probability of getting at least one head
Solution:
Total outcomes={HH,HT,TH,TT}=4
Favorable outcomes(atleast one head)={HT,TH,HH}=3
Probability of getting atleast one head = favorable outcomes/total outcomes
=3/4
Hence Probability of getting atleast one head is 3/4
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