Math, asked by garimaagnihotri2358, 1 year ago

In a simultaneous throw of two coins the probability of getting at least one head is

1/2 1/3 2/3 3/4

Answers

Answered by divyanshu02
24
Total outcomes = HH , HT , TH , TT

P(At least 1 head) = 3/4


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Answered by wifilethbridge
4

Answer:

3/4

Step-by-step explanation:

To Find: In a simultaneous throw of two coins the probability of getting at least one head

Solution:

Total outcomes={HH,HT,TH,TT}=4

Favorable outcomes(atleast one head)={HT,TH,HH}=3

Probability of getting atleast one head = favorable outcomes/total outcomes

                                                              =3/4

Hence Probability of getting atleast one head is 3/4

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