Question

in a simultaneous throw of two dice ,what is the probability of getting doublet ?​

Answer 1

E ⟶ event of getting a doublet No. of favorable outcomes = 5 {(1, 1) , (2, 2) , (3, 3) , (4, 4) , (5, 5) , (6, 6)} Total no. of possible outcomes = 36 P(E) = 6/36 = 1/6.