Question

in a single cast with two fair dice what is the chance of throwing (1)two fours
(2)a doublet
(3)five-six
(4)a sum of 7

Answer 1

the chance that is cast in single with two fair dice is 1) two fours

Answer 2

Answer:

1) P(two fours) = 1 / 36

2) P(a doublet) = 3 / 36 = 1 / 12

3) P(five - six) = 1 / 36

4) P(sum of 7) = 6 / 36 = 1 / 6

Step-by-step explanation:

total outcomes = n = 36

1) s = { (4,4) }

n(s) = 1

=> P(two fours) = 1 / 36

2) s = { (2,2) , (4,4) , (6,6) }

n(s) = 3

=> P(a doublet) = 3 / 36 = 1 / 12

3) s = { (5,6) }

n(s) = 1

=> P(five - six) = 1 / 36

4) s = { (1,6) , (2,5) , (3,4) , (4,3) , (5,2) , (6,1) }

n(s) = 6

=> P(sum of 7) = 6 / 36 = 1 / 6

Hope it is useful...