Physics, asked by ItzKaminiForYou, 9 hours ago

In a single slit diffraction experiment first minimum for lambda 1 is equal to 660 nm coincides with first maximum for wavelength lambda to calculate lambda 2

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Answered by Gujjartinku

11

Answer:

hope it will help

Explanation:

please mArk Brainliest

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Answered by xxcuteboyxx62

3

$\begin{gathered}\huge\blue{\mid{\fbox{\tt{SOLUTION}}\mid}} \\ \end{gathered}$

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