Question

In a single slit diffraction pattern, how is the angular width of central bright maximum changed, when
(i) the slit width is decreased,(ii) the distance between the slit and screen is increased,(iii) light of smaller wavelength is used ? Justify your

Answer 1

In single slit diffraction pattern, angular width of central maximum is given by,
$\Theta=\frac{2\lambda}{d}$

where $\Theta$ indicates angular width of central maximum , d indicates slit width and $\lambda$ is wavelength of monochromatic light.

i) increase, angular width is inversely proportional to slit width. when slit width decreases, angular width of central bright maximum increases.

ii) remains constant, because of angular width doesn't depend on the distance between the slit and screen

iii) decrease, because of angular width is directly proportional to wavelength of light.

Answer 2

Answer:

In single slit diffraction pattern, angular width of central maximum is given by,

\Theta=\frac{2\lambda}{d}Θ=

d

2λ

where \ThetaΘ indicates angular width of central maximum , d indicates slit width and \lambdaλ is wavelength of monochromatic light.

i) increase, angular width is inversely proportional to slit width. when slit width decreases, angular width of central bright maximum increases.

ii) remains constant, because of angular width doesn't depend on the distance between the slit and screen

iii) decrease, because of angular width is directly proportional to wavelength of light.