In a single throw of 2 dice what is the probability of getting more than 7
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0 as no no. is more than 6
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Let's take Sample Space be
{ ( 1,1 ), (1, 2 ), (1,3), ( 1, 4) , (1,5) ,( 1,6 )
...…..………….................. ( 6, 4), ( 6, 5), (6,6)}
n(S) = 36
Let A be the event of the numbers that sum is more than 7.
A = {(1,6),(2,5),(2,6),(3,4),(3,5),(3,6),(4,3),(4,4),(4,5),(4,6),(5,2),(5,3),(5,4),(5,5),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)}
n(A) = 21
P(A) = n(A)÷n(S)
===> 21/36.
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