Question

in a single throw of 2 dice what is the probabillity of getting a sum of 6​

Answer 1

Answer:

2

Step-by-step explanation:

here we are using 2 dices so it is 2

Answer 2

Answer:

5/36

Step-by-step explanation:

single throw of 2 dice [(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)]

 N(s)=36

event A=getting a sum of 6

A= [(1,5),(2,4),(3,3),(4,2),(5,1)]

N(A)=5

p(A)=N(A)/N(s)

     =5/36