Math, asked by yadavbikashshankar00, 8 months ago

In a single throw of a die, find the probability of getting :
(i) an odd number
(ii) a number less than 5
(iii) a number greater than 5
• (iv) a prime number
(v) a number less than 7
(vi) a number divisible by 3
(vii) a number between 3 and 6 • (viii) a number divisible by 2 or 3.​

Answers

Answered by af57867
9

Answer:

1) probability of getting an odd number: 1, 3, 5

P(O)= 3/6= 1/2

2) Probability of getting less than five number= 1,2,3,4

P(L)= 4/6= 2/3

3) Probability of getting greater than 5= 1

P(G)= 1/6

4) Probability of getting prime number= 2,3,5

P(p)= 3/6=1/2

5) Probability of getting less than 7= 1,2,3,4,5,6

P(l)= 6/6=1

6) Probability of getting a number divisible by 3= 3,6

P(d)=2/6=1/3

7) Probability of getting number between 3 and 6= 4,5

p(g)= 2/6=1/3

probability of getting number divisible by 2= 2,4,6

p(d)= 3/6=1/2

Answered by DINESHBORIKAR
2

Answer:

1) 3/6=1/2

2)2/3

3)1/6

4)4/6 =2/3

5)6/6= 1

6)2/6=1/3

7)2/6=1/3

8)no. divisible by 2 =3/6=1/2

no. divisible by 3=2/6=1/3

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