In a single throw of a die the probability of getting a number divisible by 3 ?with solution
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1
if a die is thrown,
S={1,2,3,4,5,6}
n(S)=6
A is the event that the number comes up is divisible by 3
A={3,6}
n(A)=2
probability of A= n(A)÷n(S)
=2/3
=1/3
S={1,2,3,4,5,6}
n(S)=6
A is the event that the number comes up is divisible by 3
A={3,6}
n(A)=2
probability of A= n(A)÷n(S)
=2/3
=1/3
yasummu:
IT IS 2/6
2/6 = 1/3
sorry i have written it by mistake
No problem
Answered by
1
We have two numbers divisible by 3
2/6=1/3 is the right answer
2/6=1/3 is the right answer
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