in a single throw of a pair a pair different dice what is the probality of getting i a prime no on dice ii a total of 9 or 11
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Total no. In dice:1, 2,3,4,5,6=6
Prime numbers are 2,3,5
P(prime number) =3/6=1/2
Sum of 9 =(3, 6)&(4,5),(6,3),(5,4)
P(sum of 9)=4/36=1/9
Sum of 11=(5,6),(6,5)
P(sum of 11)=2/36=1/18
Hope it is helpful and mark me as brainliest if you satisfied from my answer..
Prime numbers are 2,3,5
P(prime number) =3/6=1/2
Sum of 9 =(3, 6)&(4,5),(6,3),(5,4)
P(sum of 9)=4/36=1/9
Sum of 11=(5,6),(6,5)
P(sum of 11)=2/36=1/18
Hope it is helpful and mark me as brainliest if you satisfied from my answer..
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