Question

In a single throw of a pair of dice what is the probability of getting a prime number on each dice

Answer 1

n(s)=(1,2,3,4,5,6) therefore n(S)=6

lea event A be that getting a prime number on upper side of dice
n(A)=(2,3,5) therefore n(A)=3

p(A)=n(A)/n(S)
=3/6
1/2


Therefore probability of getting prime number on dice is 1/2