Math, asked by aditya5120, 1 year ago

In a single throw of dice, find the probability of getting a number (i) greater than 2 (ii) less than or equal to 2 (iii) not greater than 2. not greater. NOTE : do this question with rough work. You can also see the question in the given image question number 6.

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Answered by sdjoshi2502
24
probability=No.of favorable outcomes/No.of possible outcomes
POSSIBLE OUTCOMES=6
I) Favourable outcomes={3,4,5,6}=4
P=4/6=2/3
II)Favourable outcomes={1,2}=2
P=2/6=1/3
III)Favourable outcomes={1,2}=2
P=2/6=1/3

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aditya5120: but in my book thurd part answer is 1/3 who it is possible can you explain it . PLEASR
sdjoshi2502: tnx for letting me know the answer in the book.
aditya5120: (i) 2/3 (ii) 1/3 (iii) 1/3 ok please explain who it is possible
sdjoshi2502: in the first condition it is <2 so the outcomes would be 3,4,5,6 so the total no.of outcomes are 4 by putting this value in formula u get the result
sdjoshi2502: the same thing applies to other conditions
Answered by hrishikanth285
5

Answer:(i)4/6 (ii)3/6 (iii)2/6


Step-by-step explanation:(i)numbers greater than 2 are 4.Probability=4/6

(ii)numbers less than or equal to 2 are 3.Probability=3/6

(iii)numbers less than 2 are 2.Probability=2/6


aditya5120: can you explain the thurd part breafly
aditya5120: please explain it fast
aditya5120: please please
sdjoshi2502: the answers must be in the simplified form
sdjoshi2502: numbers less than 2 on a dice is 1 also it is given less than and EQUAL TO 2 so the favorable outcomes would be 2 in number
aditya5120: you can see the question image their is no equal to
aditya5120: 1) 2/3 2) 1/3 3) 1/3
aditya5120: explain it after it I will give you a brainlist
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