in a single throw of dice what is the probability to get a number greater or equal to 4?
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In a single throw..
There are total 6 incidents.
In these the Number5 and 6 are greater
than 4.
so probability=Number of favor incidents/totalnumber of incidents
=2/6
=1/3
There are total 6 incidents.
In these the Number5 and 6 are greater
than 4.
so probability=Number of favor incidents/totalnumber of incidents
=2/6
=1/3
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