In a single throw of three dice, find probability of getting a total of 17 or 18 .
Plz tell fast
Shaina11:
Answer is 1/54 plz explain how
Answers
Answered by
19
basically we have to make .....their output ...
like
events 111,222,333,444,555,666,
112,113,114,115,116,k
121,122,123,124,125,
make like all event
and then find the value which conatin
sum, 18 or 17
that is your ans
by toal 216
18 = (666)=1/216
17= 665,656,566=3/216
1/216+3/216
4/216
1/54
like
events 111,222,333,444,555,666,
112,113,114,115,116,k
121,122,123,124,125,
make like all event
and then find the value which conatin
sum, 18 or 17
that is your ans
by toal 216
18 = (666)=1/216
17= 665,656,566=3/216
1/216+3/216
4/216
1/54
Of which 17 or 18 can be obtained by 5,6,6; 6,5,6; 6,6,5; 6,6,6 So , favourable outcomes : 4
So , probablity : 4/216 = 1/54
OK thank you
Np ✌
bhai mene bhi vhi kra hai
bus alag alag probiltiy nikali thi
Mai toh Kuch bola hi nahi?
Hmm your answer is right too rivak
nhi aapne comment me ans diya isliye
Ohh sorry for that!
Similar questions