Question

In a single throw of two coins, find the probability of getting:

(A) Both tails

(B) Atleast one tail
(you have to find probability it's not a mcq question)​​

Answer 1

here is your answer

hope it helpful for you

Answer 2

Answer:

Sample space{HH,HT,TH,TT}

n(s)=4

Event A be the probability of getting both tails

A{TT}

n(a)=1

p(a)=n(a)/n(s)

=1/4

Event B be the probability of getting at least one tail

B{HT,TH,TT}

n(b)=3

p(a)=n(a)/n(s)

=3/4