In a single throw of two coins find the probability of getting 1 both tails 2 at least 1 tail 3 at the most 1 tail
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Answer:
1. both tail= 1/4
2.at least 1 tail= 3/4
3.at most 1 tail= 1/2
Step-by-step explanation:
we know that two coins are throwing in the air so there are basically four options H H T T [ H denotes head]
[ T denotes tail]
So in a single throw chances will be,,
HH TT HT TH
1.Now both will be tail only for TT,so 1/4
2.at least 1 tail,,in three places TH HT TT,so probability= 3/4
3.at most 1 tail,,in two cases TH HT,so probability= 2/4=1/2
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