In a single throw of two coins, find the probablity of getting 1. both tails 2. at least 1 tail 3. at the most 1 tail
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Answered by
90
P={hh,ht,the,TT}
1)Q={tt} probability of q= 1/4
2) S={ht,th,TT} probability of s= 3/4
3)R={th,ht} probability of r = 1/2
1)Q={tt} probability of q= 1/4
2) S={ht,th,TT} probability of s= 3/4
3)R={th,ht} probability of r = 1/2
Answered by
65
1. P(both tails) =
favorable outcomes/total outcomes
1/4
2. P(at least one tail) = 3/4
3. P(at most one tail) = 2/4 = 1/2
favorable outcomes/total outcomes
1/4
2. P(at least one tail) = 3/4
3. P(at most one tail) = 2/4 = 1/2
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