Question

in a single throw of two dice find the probability of getting a sum from different from 8​

Answer 1

Answer:

Probability = total number of favourable items /total number of favourable outcomes

=8/12

=2/3

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Answer 2

Answer:

1/3

Step-by-step explanation:

There are total 36 possibilities if one two dices are thrown

1,1 1,2 1,3 1,4 1,5 1,6

2,1 2,2 2,3 2,4 2,5 2,6

3,1 3,2 3,3 3,4 3,5 3,6

4,1 4,2 4,3 4,4 4,5 4,6

5,1 5,2 5,3 5,4 5,5 5,6

6,1 6,2 6,3 6,4 6,5 6,6

There are 5 possibilities for getting sum as 8

Probability=no of possible outcomes/total no. Of outcomes

=5/36