Question

In a single throw of two dice find the probability of neither getting a double or a total of 10

Answer 1

Answer:

Step-by-step explanation:

Total no.of outcomes=6*6=36.

Total pair of doublets=6[(1,1);(2,2);(3,3);(4,4);(5,5);(6,6)]

total pair of numbers adding up to 10=3[4,6;6,4;5,5]

∴ total no.of pairs of doublets and and a total of 10=6+3

                                                                                    =9.

∴P(neither a doublet nor a total of 10)=9/36

                                                                 =1/4