in a single throw of two dice,the probability of:
1) a doublet
2) an odd number as a sum
3) an odd number on dice and a number less than or equal to 4 on the other dice
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2
(1)6/36=1/6
(2)18/36 =1/2
(3)favourale outcomes:1,1 1,2 1,3 1,4
3,1 3,2 3,3 3,4
5,1 5,2 5,3 5,4
no.of favourable outcomes=12
12/36=1/3
(2)18/36 =1/2
(3)favourale outcomes:1,1 1,2 1,3 1,4
3,1 3,2 3,3 3,4
5,1 5,2 5,3 5,4
no.of favourable outcomes=12
12/36=1/3
Keerthi111:
may l know how did u solve 3rd one
Answered by
1
The probability is--
1)6/36=1/6
2)18/36=1/2
3)12/36=1/3
1)6/36=1/6
2)18/36=1/2
3)12/36=1/3
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