Question

In a single throw of two dice,the probability of getting doublet i.e. getting the same number on both dice is
(a) 1/2
(b) 1/6
(c) 1/4
(d) 1/12​

Answer 1

$\textbf{Given:}$

$\text{Two dice are thrown}$

$\textbf{To find:}$

$\text{The probability of the same number on both dice}$

$\textbf{Solution:}$

$\text{When two dice are thrown,}$

$\textbf{Sample space}$

S={(1,1), (1,2), (1,3), (1,4), (1,5), (1,6)

(2,1), (2,2), (2,3), (2,4), (2,5), (2,6)

(3,1), (3,2), (3,3), (3,4), (3,5), (3,6)

(4,1), (4,2), (4,3), (4,4), (4,5), (4,6)

(5,1), (5,2), (5,3), (5,4), (5,5), (5,6)

(6,1), (6,2), (6,3), (6,4), (6,5), (6,6)}

$\text{Let A be the event of getting same number on both dice}$

A={(1,1), ------, --------, -------, --------, ------

--------, (2,2), ------, --------, -------, ------

--------,--------, (3,3), ------, --------, -------

------, --------, -------, (4,4), ------, ---------

------, --------, -------, --------,(5,5),---------

------, --------, -------, --------, -------, (6,6)}

$\text{Then,}$

$\bf\,P(A)=\dfrac{n(A)}{n(S)}$

$\implies\,P(A)=\dfrac{6}{36}$

$\implies\bf\,P(A)=\dfrac{1}{6}$

$\textbf{Answer:}$

$\textbf{Option (b) is correct}$.

Answer 2

Answer:

options B) is the correct answer is 1/6