Question

in a single throw of two dice , what is the possiblity that the sum is 9.​

Answer 1

Answer:

1/9

Step-by-step explanation:

Sample Space =

{ (1,1), (1,2), (1,3) , (1,4), (1,5), (1,6)

{ (2,1), (2,2), (2,3) , (2,4), (2,5), (2,6)

{ (3,1), (3,2), (3,3) , (3,4), (3,5), (3,6)

{ (4.1), (4,2), (4,3) , (4,4), (4,5), (4,6)

{ (5,1), (5,2), (5,3) , (5,4), (5,5), (5,6)

{ (6,1), (6,2), (6,3) , (6,4), (6,5), (6,6) }

Total number of sample space space = n(s) = 36

Let A be the event of getting sum of 9.

favourable outcomes of A = {(3,6), (4,5), (5,4), (6,3)}

Number of favourable outcomes of A = n(A) = 4

Probability or possibility = n(A)/n(s) = 4/36 = 1/9