Question

In a single throw of two dices, what is the probability of getting a sum of 8 or 11? Options : 1. * 1/36 2. * 3/36 3. * 5/36 47/36​

Answer 1

Answer:

number of possible outcomes is (6×6)=36.

Let S be the sample space. Then, n(S) = 36.

Let E = event of getting a total of 8. Then,

E={(2,6),(3,5),(4,4),(5,3),(6,2)} and, therefore, n(E) = 5.

∴ P(getting a total of 8) =P(E)=n(E)n(S)=536.