Question

In a single throw with two dice find the chance of throwing at least 8( or more than7)

Answer 1

In a single throw with two dice find the chance of throwing at least 8 (or more than7) is 5 / 12.

• A die has 6 numbers. Since 2 dice are thrown, thus the total number of ways the dice can fall is 36.

• 8 can be obtained in the following 5 ways - (2,6) , (3,5) , (4,4) , (5,3) , (6,2)

• 9 can be obtained in the following 4 ways - (3,6) , (4,5) , (5,4) , (6,3)

• 10 can be obtained in the following 3 ways - (4,6) , (5,5) , (6,4)

• 11 can be obtained in the following 2 ways - (5,6) , (6,5)

• 12 can be obtained in the following 1 way - (6,6)

• Thus, the chances of getting at least 8 are :

        =(5+4+3+2+1)​ / 36

        =15 / 36

        =5 / 12