Question

In a single throw with two dice, find the probability that their sum is a multiple of either 3 or 4?

a. 1/3

b.1/2

c.17/36

d.5/9

Answer 1

Their sum can be 3,4,6,8,9,12

For two dice, any number from 2 to 7 can be get in (n-1) ways and any number from 8 to 12 can be get in (13 - n) ways.

Then possible ways are 2 + 3 + 5 + 5 + 4 + 1 = 20 possible cases.

So probability is (20/36)=(5/9)   ans D