Question

In a single throw with two dice find the probability that their sum is a multiple of 4 or 5

Answer 1

HEY Buddy....!! here is ur answer

E = (1,3),(2,2),(3,1),(1,4),(2,3),(3,2),(4,1)

=> n(E) = 7

n(S) = 6² = 36

As we know that :

$p = \frac{n(E)}{n(S)} \\ \\ = > p = \frac{7}{36}$

So, the probability will be 7/36

I hope it will be helpful for you..!!

THANK YOU ✌️✌️